Originals from Pat a Mat 30 - second part

Comment on original for solving:
No. 884 and ...

Solution:

1...Jb1 2.e3! Jc3#
1,,,Jf1 2.c3! Je3#

1.e3 Kf5 2.exd2 e4#
1.c3 Sb5 2.cxd2 c4#

2x2 symmetrical phases in tempo position. If black needn't move, white could have mated him in many ways. (JL)

Comment on original for solving:
... 885 are simpler, but don't forget to look for set play.

Solution:

1...Sd5 2.Jb4 Sd4#

1.Kc4 Sd4 2.Sb4 Sd5#

Elegant echo with set play and exchange of white moves. (JL)

Comment on original for solving:
886 has in 2 solutions the same theme as ...

Solution:

1.Db4 Jc8 2.Db7+ d7#
1.Dg3 d7 2.Dc7 Jc8#

Again exchange of white moves, this time with bQ moves along pin line. (JL)

Comment on original for solving:
... 887 in 3 solutions.

Solution:

1.Dc3 Db6! (Dc5?, Dxe5?) 2.Dg3 Dd8#
1.Vd3 Dc5! (Dxe5?, Db6?) 2.Vg3 De7#
1.Va3 Dxe5! (Db6?, Dc5?) 2.Vg3 Df6#

Two of three first white moves are cyclically wrong, but it isn't dual avoidance as black moves have positive motive allowing good white continuations instead of negative dual avoidance motives. (JL)

Comment on original for solving:
Jozef tries 3 solutions too, successfully.

Solution:

1.Sxf4 bxc5 2.Sb8 Dxb8#
1.Jexf4 Dd2 2.Jd3 Dc3#
1.Jhxf4 Dh8 2.Dxb2+ Dxb2#

3 captures at f4 have different motivations (line clearance, the only way to d3, the only square for S withdrawal without negative motive respectively) and the rest is little unified, despite this I have good feeling. (JL)

Comment on original for solving:
Czecho-slovak pair works well, is seems - they compose in every possible genre, they had #3 in PaM 28, here is h#3 and further s#3 too.

Solution:

a) 1...Je7 2.Jd7 Sxf5 3.Je5 Sb4#

b) 1...Jf8 2.Sd8 Sg6 3.Ke7 Sc5#

Echo model mates. (JL)

Comment on original for solving:
Michal is the master od echo diagonal-orthogonal.

Solution:

a) 1.Vxc2 d7 2.Vxc3 (Ve2?) Vh2 3.Ve3 Jd2#

b) 1.Sxd6 cxd3 2.Sc5 (Sf4?) Sh2 3.Se3 Je5#

Echo diagonal-orthogonal: opening of white lines, choice of move, anticritical moves, blocking and model mate. (JL)

Comment on original for solving:
Last, but not least, we have here relatively new name from Ukrajina, Anatolij presents zeroposition with nice echo.

Solution:

a) 1.Vh3 Se3 2.De1+ Kb2 3.Kf5 Kc2 4.Kg4 Kd3 5.Kh4 Ke4 6.Jf2+ Kf5 7.Jg4 Kg6 8.Dg3 Sg5#

b) 1.Vg3 Sd3 2.Dh4 Kb2 3.Ke5 Kc3 4.Kf4 Kd4 5.Kg4 Ke5 6.Jg5 Kf6 7.Kh5 Kg7 8.Vg4 Sg6#

Echo of ideal mate at far edge of board is powered by unified use of black line pieces interferences. (JL)