Originals from Pat a Mat 23 - first part


This is the 1st of 4 files containing Pat a Mat 23 originals. The others are:
Second part
Third part
Fourth part

The solutions are already here. Note Slovak signs for pieces: K - king, D - queen, V - rook, S - bishop, J - knight, p - pawn.

Comments to #2 originals, originally in Slovak, are by Peter Gvozdják. Translated to English by Juraj Lörinc.

Cornelis Groeneveld
at Aalten, NL
193 Pat a Mat 23 - December 1998

Comment on original for solving:
Cornelis' 193 has 2 phases with changes.

Solution:
1.Jb4? hr. 2.Jbd5#, 1...Je3, e3 2.Dc7, Dd4#, 1...c6!, 1.De1! tempo, 1...Jf1~, Je3, e3, f2, Ke3 2.e3, Dg3, Db4, Dxf2, Jd5#.

Change of two mates with classical key.









#2 (7+7)

Vladimir Golubenko
Novgorod, RUS
194 Pat a Mat 23 - December 1998

Comment on original for solving:
Vladimir in 194 changes functions of moves.

Solution:
1...Ve4~ 2.Dd5#, 1.Sg4? hr. 2.Dxf5#, 1...Vf~ 2.De6#, 1...Vf6!, 1.Jbc7? hr. 2.Dd5#, 1...Vd4 2.De6#, (1...Db3 2.Vxe4#), 1...Dd3!, 1.Jdc7! hr. 2.De6#, 1...Vf6 2.Dd5#, (1...Db3, Kf6 2.Dd4, Dxd7#)

Changes of function (author).









#2 (6+9)

John Rice
Surbiton, GB
195 Pat a Mat 23 - December 1998

Comment on original for solving:
John gives "remaining" 195 from Spisska Borovicka '97.

Solution:
1.Jb3? hr. 2.Ke6A, Kf5B#, 1...Sg6, Sf7 2.Ke6A, Kf5B#, 1...Sg4!, 1.Je6? hr. 2.Kf5B, Ke4C#, 1...Sxf3, Sg4 2.Kf5B, Ke4C#, 1...Sg6!, 1.Jf5! hr. 2.Ke4C, Ke6A#, 1...Sf7, Sxf3 2.Ke4C, Ke6A#

The theme of Spisska Borovicka was set to be combination of mutiple threats with partial defences.









#2 (9+9)

Jevgenij Balashov
Omsk, RUS
196 Pat a Mat 23 - December 1998

Comment on original for solving:
Jevgenij in 196 changes battery mates.

Solution:
1.Je4? hr. 2.Jf6#, 1...Vg6, Va6 2.Jc1, Je1#, 1...Jg8!, 1.Jc5! hr. 2.Se6#, 1...Vg6, Va6 2.Jb1, Jf1#

Change of two mates from half-battery.









#2 (11+7)

Marjan Kovacevic
Zemun, YUG
dedicated to L. Lacny
197 Pat a Mat 23 - December 1998

Comment on original for solving:
When Marjan gave me 197 for Pat a Mat, I told him:"Finaly, after longer time, you did great composition." Of course, the quality of most of his works is much better than average, but I was delighted by the fact, that such a puritan (in terms of constructional principles) broke some of these tenets: otherwise there should be no 197...

Solution:
1...De4, Jf4, Df4 2.Se6A, Vg5B, Jg3C#, 1.Dc3! hr. 2.De5#, 1...De4, Jf4, Df4 2.Vg5B, Jg3C#, Se6A

Absolutely original scheme for Lacny theme and modern twomover from absolute top. All thematical mates use dual avoidance in both phases.









#2 (12+7)

Anatolij Slesarenko
Valerij Shanshin

Dubna, RUS
Os KGZ
198 Pat a Mat 23 - December 1998

Comment on original for solving:
We have also the world champion in 198.

Solution:
1.f8D? hr. 2.Dxf6#, 1...Jxd3, Sxc3 2.Dd6, De4A#, 1...Jxf7! 1.Kb3? hr. 2.De4A, Df2B#, 1...Jxd3, Sxc3 2.Vc4C, Dxc3#, 1...f2! 1.Sf4! hr. 2.Vc4C#, 1...Jxd3, Sxc3 2.De4A, Df2B#.

Shedey, Rudenko, le Grand, Zagorujko. (authors)









#2 (10+10)

Peter Gvozdják
Bratislava, SVK
199 Pat a Mat 23 - December 1998
dedicated to V. Jerochin

Comment on original for solving:
Author of these reflections dedicates own composition 199 (in which we cannot speak about holding any traditional principles) to the author of first fourfold work with the same theme: which one?

Solution:
1.Jcxb3? hr. 2.c4A#, 1...Kxd5 2.Vxc5A#, 1...c4!, Df3! 1.dxe6? hr. 2.Vxc5B#, 1...Kd5 2.Df5C#, 1...e3!, exd6! 1.Sh3? hr. 2.Df5C#, 1...Kxd5 2.Dxe6D#, 1...Vxf6!, Df3! 1.e3? hr. 2.Dxe6D#, 1...Kxd5 2.Jc4E#, 1...Vxf6!, Vxd6! 1.Vxa6! hr. 2.Jc4E#, 1...Kxd5 2.c4A#

5-fold Ukraiinian theme, it is called cyclic le Grand too. First time without promoted force, but with double refutations in 4 tries. (The very first Ukraiinian theme was done by John Rice in 1961.) (author)









#2 (14+9)

Karol Mlynka
Bratislava, SVK
dedicated to J. Taraba-50
200 Pat a Mat 23 - December 1998

Comment on original for solving:
And then Karol in his dedicated 200 (sent in time!) duly stirs letters: he separates threats and changes the mates and pairs of them.

Solution:
1.Da1? hr.2.Dd4A, De5B, Jf6C#, 1...Df8a, Db6b, Jh3e, Dd6c (Je4f) 2.AB, BC, CA, A, B, C, 1...c3!, 1.Ve6? hr.2.Jf6C, Je3D, Ve5E#, 1...Df8a, Db6b (Vh3g), Dd6c, Jh3e, a1Di, Dd7h, Jxe6d 2.DE, EC, CD, C, D, E, Sb7K#, 1...Je4!, 1.Vxc4! hr.2.Vd4F, Jf4G, Jc3H#, 1...Df8a (Dd6c, Jh3e), Db6b, Vh3g, Je4f, Dd7h (a1Di), Je6d 2.HF, GH, FG, F, G, H, D

Zagorujko after a, b, c, d, e and some other changes. 6 cycles in 3 phases. (author)









#2 (11+13)

Harri Hurme
Espoo, FIN
201 Pat a Mat 23 - December 1998

Comment on original for solving:
Lastly, Harri's contribution 201 is very unusual, but very interesting: when in 1997 on Pula congress Petrovic's idea tourney award was presented (reciprocal change, black knights defend to the same square and white knights mate to the same square, those squares can be the same or different), the judge didn't consider 201 at all. Let's look at it and study it closely.

Solution:
1.Sf2? hr. 2.Ve4#, 1...Jed5, Jfd5 2.Jdf8A, Jgf8B#, 1...Jxd7! 1.Sd6! hr. 2.Jc7#, 1...Jed5, Jfd5 2.Jgf8B, Jdf8A#

Reciprocal changes reached by 4 knights on the same squares - theme of N. Petrovic. Non-orthodoxal: promoted force. Orthodoxal: legal position, all white pieces play actively in solution, at least one function.









#2 (14+11)

Comments to Juraj Lörinc.
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