My works 302 - 308



Juraj Lörinc, 4th-5th HM Problem-Echo 2000/2-1/09, Notes: C001 Sent: 302, fairy h#2 can be found here.

After learning the theme of this Problem-Echo TT I was immediately excited as I knew there are immense possibilities in h#2 with grasshoppers and nightriders. You can remember that CCM devoted to these many pages: It was pure coincidence, that I wanted to set exactly that theme for some CCM TT, but seeing Problem-Echo announcement I abandoned that idea.

The problem shows creation of reciprocal batteries simply by capture of opposite unit half-pinned by rear piece. The double-check mate follows.

Personal rating: C.



Juraj Lörinc, 2nd Comm Problem-Echo 2000/2-2/06, Notes: C002 Sent: 303, fairy h#2 can be found here.

The precise comment on content can be found nearby diagram. I was slightly disappointed to find out that this h#2 got only 2nd Comm within the bunch of 12 problems, while previous one got HM within another problems. In Problem-Echo tourneys the result depends on the level of marks given by judges, but I think 303 is better than 302.

Personal rating: B.



Juraj Lörinc, 2nd HM Problem-Echo 2000/2-3/04, Notes: C003 Sent: 304, fairy h#2 can be found here.

Rather simple helpmate, another example of undeserved HM.

Personal rating: C.



Juraj Lörinc, 1st Prize Problem-Echo 2000/2-3/05, Notes: C004 Sent: 305, fairy h#2 can be found here.

Surely one of my best fairy helpmates. The motivation is unusually rich, the power of all moves is very good. B1 twice indirectly unguards (by line closing as well as hurdle removal) and opens line for W1. B2 then moves bK into not yet formed mating net and W1 is triple antibattery mate. Strong ortho-diagonal correspondence. I can't understand why one of judges (Klaus Funk) objected so much against cookstopping Be1. I'm sure he didn't try to make the problem correct without him. Given position, it is the result of the very long fight for economy and against cooks. In fact, there is ONLY one cookstopper, wK (who should have been present anyway) stops cooks too.

Personal rating: A.


Michel Caillaud
Juraj Lörinc

3rd Prize Wola Gulowska C 15.5.2000
Notes: C005 Sent: 306

1...Rg4 a 2.VAd4+ A LExd3#
1...Rg5 b 2.Sd5+ B LExd3#
1...Rg6 c 2.Sd6+ C LExd3#
1...Ke7 2.Rxf7+ LExf7#

1.PAd2! zz
1...Rg4 a 2.Sd6+ C Rd4# (2.Sd5+? B)
1...Rg5 b 2.VAd4+ A Rd5# (2.Sd6+? C)
1...Rg6 c 2.Sd5+ B Rd6# (2.VAd4+? A)
1...Ke7 2.Rxf7+ LExf7#

Fairy section of Wola Gulowska 2000 was dedicated to s#2 with leo, vao and pao. Again this theme was very inspiring for me. I quickly set a few schemes and subsequently tried to finish them. Some of them successfully, some in vain. The latter I then offered to a few friends. Scheme of 306 had initially the form of reciprocal change, it was Michel's idea to extend it into Lacny cycle and then to finish it in the mutate form. Of course, this way the construction is heavier, but the content more interesting. Just analyse the ways of taking care of flight e7... In my opinion very good selfmate with fairy pieces.

And it isn't only my opinion. It was my very first problem that was reprinted in "Selected problems" column of magazine The Problemist by John Rice. This is real honour for me - but there were reprinted 2nd and 1st Prize as well and this is an indirect proof that Wola Gulowska 2000 had very good level!

Personal rating: A.









s#2* (15+12)
1+1 leo, 2+2 pao (d3), 2+2 vao (a3)

Juraj Lörinc
Michel Caillaud

6th HM Prize Wola Gulowska C 15.5.2000
Notes: C006 Sent: 307

1.LEd5! zz
1...Rb6 A 2.LEc4+ Sxc4# B
1...Sc4 B 2.b5+ Bxb5# C
1...Bb5 C 2.Rb6+ Rxb6# A

Cycle of 1st and 2nd black moves. It is interesting that the extension to 4 elements is possible with orthodox force only as it is demonstrated by Michel Caillaud's s#2 from PaM.

Personal rating: C.









s#2 (12+6)
vao a8, lao g8, 1+1 pao

Juraj Lörinc
Ladislav Salai jr.

2nd HM Prize Wola Gulowska C 15.5.2000
Notes: C007 Sent: 308

1.PAg2? th. 2.Rxd5+ LExd5# A
1...VAf3 a 2.Sxb3+ PAxb3# B
1...PAf3 b 2.Sxe2+ VAxe2# C
1...LEg1!

1.PAg3? th. 2.Sxb3+ PAxb3# B
1...LEf3 c 2.Sxe2+ VAxe2# C
1...VAf3 a 2.Rxd5+ LExd5# A
1...LEe4!

1.PAg4! th. 2.Sxe2+ VAxe2# C
1...PAf3 b 2.Rxd5+ LExd5# A
1...LEf3 c 2.Sxb3+ PAxb3# B

I wonder who in fact discovered this mechanism of three intersecting chinese lines alternatively activated and deactivated by both sides. It allows different expressions of carousel change combined with le Grand between any two of three of phases as here, compare e.g. to #2 by MD and JL. I returned to this scheme a few more times (and recently I composed some new examples syntheses of various change themes).

Personal rating: B.









s#2 (9+16)
2+3 vao, 2+2 pao, 0+1 leo

Comments to Juraj Lörinc.
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