Lacny theme 2

As is already mentioned in announcement of Lacny theme TT, in 1969 Slovak newspaper Pravda organized similar tourney. Here you can see awarded works from this TT that contain pure Lacny theme. In these days composers didn't distinguish between pure and threat form of Lacny theme (second nowadays known as Dombro-Lacny, short-cut Lacny - in the above mentioned announcement it is stressed Dombro-Lacny is unthematical).

Orthodox section of TT Pravda C 1.11.1969 was judged by Juraj Brabec.
Ludovit Lacny
1st Prize Pravda C 1.11.1969

Set play:
1...Bxh7 2.Sxc2#
1...Bc3 2.Qc5#
1...Qe3 2.Qd6#
1...Rxe4 2.Rd6#

Solution:
1.Sc3! threats 2.h8Q#
1...Bxh7 2.Qc5#
1...Bc3 2.Qd6#
1...Qe3 2.Rd6#
1...Rxe4 2.Sxc2#









#2 (9+13)
Jan Valuska
2nd Prize Pravda C 1.11.1969

a) 1.Be2! zz
1...Sd2~ 2.Rc3#
1...b5 2.Rc5#
1...e4 2.R5d4#
1...Rc2~ 2.R3d4#

b) 1.Bf7! zz
1...Sd2~ 2.Rc5#
1...b5 2.R5d4#
1...e4 2.R3d4#
1...Rc2~ 2.Rc3#









#2 (12+11)
b) a4 -» a2, g6 -» f3
Ivan Tatransky
3rd Prize Pravda C 1.11.1969

Set play:
1...Kd4 2.Qd5#
1...Bd3 (Bd5) 2.Bd6#
1...Kf4 2.Sg6#
1...Sf6 2.Bf6#

Solution:
1.Sd2! threats 2.Qe4#
1...Kd4 2.Bf6#
1...Bd3 (Bd5) 2.Qd5#
1...Kf4 2.Bd6#
1...Sf6 2.Sg6#









#2 (11+10)
Jan Valuska
1st HM Prize Pravda C 1.11.1969

a) 1.Rxb4+!
1...Kc5 2.Sd3#
1...Ke3 2.Qxa7#
1...Kc3 2.Sd5#
1...Ke5 2.Qh8#

b) 1.Rxf4+!
1...Kc5 2.Qxa7#
1...Ke3 2.Sd5#
1...Kc3 2.Qh8#
1...Ke5 2.Sd3#

c) 1.Rxd6+!
1...Kc5 2.Se4#
1...Ke3 2.Qxa7#
1...Ke5 2.Sc4#
1...Kc3 2.Qh8#

d) 1.Rxd2+!
1...Kc5 2.Qxa7#
1...Ke3 2.Sc4#
1...Ke5 2.Qh8#
1...Kc3 2.Se4#









#2 (9+7)
b) b5 -» f6
c) = b) + e7 -» a5
d) = c) + f6 -» e2, -c2
Jozef Taraba
2nd HM Pravda C 1.11.1969

a) 1.Qf7! zz
1...Rh5 2.Rxg4#
1...Kf4 2.Rd4#
1...Jf~ 2.d3#

b) 1.Qh6! zz
1...Rh5 2.d3#
1...Kf4 2.Rxg4#
1...Jf~ 2.Rd4#









#2 (9+7)
b) a5 -» h3
Jan Valuska
3rd HM Pravda C 1.11.1969

Set play:
1...Kc5 2.Sc6#
1...Kc3 2.Bd6#
1...Kxa5 2.Qe1#

Solution:
1.Bc4! zz
1...Kc5 2.Bd6#
1...Kc3 2.Qe1#
1...Kxa5 2.Sc6#









#2 (14+6)
Josef Retter
4th HM Pravda C 1.11.1969

Try:
1.d8Q? zz
1...Kxc5 2.Se6#
1...Ke5 2.Bf6#
1...Ke3 2.Qg1#
1...Kxc3!

Solution:
1.Bd5! zz
1...Kxc5 2.Qe1#
1...Ke5 2.Sc6#
1...Ke3 2.Bf6#









#2 (16+3)

Comments to Juraj Lörinc.
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